document.write( "Question 453354: an aircraft carrier left port 53 and traveled west an an average speed of 10km/h. a submarine left three hours later and traveled in the opposite direction with an average speed of 10km/h. how long does the submarine need to travel before the ships are 150km apart? \n" ); document.write( "
Algebra.Com's Answer #314392 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
3x10 kph+20x=150
\n" ); document.write( "20x=120
\n" ); document.write( "x=6
\n" ); document.write( "It will be 6 hours before the two craft are 150 km apart..
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