document.write( "Question 453354: an aircraft carrier left port 53 and traveled west an an average speed of 10km/h. a submarine left three hours later and traveled in the opposite direction with an average speed of 10km/h. how long does the submarine need to travel before the ships are 150km apart? \n" ); document.write( "
Algebra.Com's Answer #314392 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 3x10 kph+20x=150 \n" ); document.write( "20x=120 \n" ); document.write( "x=6 \n" ); document.write( "It will be 6 hours before the two craft are 150 km apart.. \n" ); document.write( " |