document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458301>Question 458301</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi I submitted questions but I never recived a confirmation e mail so I will re submit. I am having trouble with a few problems I do not know if I am setting them up the right way.  # a number increased by two -third is 35 find the number. # 2 twice the diffrence of a number and 8 is equal to three times the sum of the number and 3. Find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314384 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> letnumber be x<BR>\n" );
document.write( "2/3 of number = 2x/3\r<BR>\n" );
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document.write( "x+2x/3 =35<BR>\n" );
document.write( "multiply by 3\r<BR>\n" );
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document.write( "3x+2x=105<BR>\n" );
document.write( "5x=105 <BR>\n" );
document.write( "/5<BR>\n" );
document.write( "x=21<BR>\n" );
document.write( "...<BR>\n" );
document.write( "2(x-8)=3(x+3)\r<BR>\n" );
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document.write( "2x-16=3x+9<BR>\n" );
document.write( "2x-3x=25<BR>\n" );
document.write( "-x=25<BR>\n" );
document.write( "x=-25 </SPAN>\n" );
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