document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458255>Question 458255</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Still lost, please help!!\r<BR>\n" );
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document.write( "Lead pipes and solder are often found in older buildngs. Unfortunately, as lead decays, toxic chemicals can get in the water resting in the pipes. The half-life of lead is 22 yr. What is the decay rate?  Thamks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314358 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The half-life of lead is 22 yr. What is the decay rate? <BR>\n" );
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document.write( "Let \"r\" be the remainder rate :<BR>\n" );
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document.write( "Solve: (1/2)Ao = Ao(r)^22)<BR>\n" );
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document.write( "r^22 = (1/2) <BR>\n" );
document.write( "r = 0.5^(1/22)<BR>\n" );
document.write( "r = 0.97<BR>\n" );
document.write( "Decay rate = 1-0.97 = 3%<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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