document.write( "Question 458121: The distance between each of the bases on a baseball diamond is 90ft. A catcher often has to throw from home to 2nd base in order to get a player who is stealing bases out. How far does a catcher have to throw in this situation? \n" ); document.write( "
Algebra.Com's Answer #314235 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The distance between each of the bases on a baseball diamond is 90ft. \n" ); document.write( " A catcher often has to throw from home to 2nd base in order to get a player who is stealing bases out. \n" ); document.write( " How far does a catcher have to throw in this situation? \n" ); document.write( ": \n" ); document.write( "Solve this as a right triangle, the distance from home to 2nd is the hypotenuse(c), so you have: \n" ); document.write( ": \n" ); document.write( "c = \n" ); document.write( "c = 127.28 ft from home to 2nd \n" ); document.write( " \n" ); document.write( " |