document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458087>Question 458087</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bicycle leaves town at 14mph at 8 a.m. A car leaves at 11 a.m., in the same direction at 45 mph. How many minutes after 11 a.m. is it when the car overtakes the bicycle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314220 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> from  8 am till 11 am is three hours<BR>\n" );
document.write( "the bike had a three hour head start at 14 mph 3*14=42 miles<BR>\n" );
document.write( "as the bike is going 14 mph and the car at 45 from that point we need to calculate the gain on the bike.<BR>\n" );
document.write( "The car is gaining 45-14 =31 mph.<BR>\n" );
document.write( "So how long in minutes will it take the car to make up 42 at 31 mph<BR>\n" );
document.write( "42/31*60  about 81 minutes after 11am or about 12:21 pm<BR>\n" );
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