document.write( "Question 457930: how to solve 3cot^2 x-4csc x=1 on the interval 0≤x≤2∏ \n" ); document.write( "
Algebra.Com's Answer #314215 by stanbon(75887)\"\" \"About 
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solve 3cot^2 x-4csc x=1 on the interval 0≤x≤2∏
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\n" ); document.write( "3(csc^2-1)-4csc = 1
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\n" ); document.write( "3csc^2 -4csc -4 = 0
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\n" ); document.write( "Factor:
\n" ); document.write( "3csc^2-6csc+2csc-4 = 0
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\n" ); document.write( "3csc(csc-2)+2(csc-2) = 0
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\n" ); document.write( "(csc-2)(3csc+1) = 0
\n" ); document.write( "csc(x) = 2 or csc(x) = -1/3
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\n" ); document.write( "x = pi/4 or (3/4)pi and csc^(-1/3) does not exist
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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