document.write( "Question 458045: A square is to be built inside a circular area. Each corner of the square touches the circle. If the radius of the circle is 3, how much greater is the area of the circle than the square?
\n" ); document.write( "A. 9-9/2pi, B. 9-9pi, C. 9-9pi, D. 9pi-9, E. 9pi-18\r
\n" ); document.write( "\n" ); document.write( "I already did 3.14x9= 28.26 area of the circle.
\n" ); document.write( "Which is 9pi\r
\n" ); document.write( "\n" ); document.write( "Which one is it?
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Algebra.Com's Answer #314190 by htmentor(1343)\"\" \"About 
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The diameter of the circle forms the diagonal of the square. The diagonal of
\n" ); document.write( "the square makes an isosceles triangle.
\n" ); document.write( "The length of the other two sides is \"6%2Fsqrt%282%29\". The area of the square is \"%286%2Fsqrt%282%29%29%5E2+=+36%2F2+=+18\"
\n" ); document.write( "The difference of the areas is: \"9pi+-+18\"
\n" ); document.write( "Ans: E
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