document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458028>Question 458028</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6x^3=3x-7x^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314173 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314173\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can factor out x so one solution is x=0<BR>\n" );
document.write( "6x^3+7x^2-3x=0<BR>\n" );
document.write( "x*(6x^2+7x-3)=0<BR>\n" );
document.write( "you want factors of -18 which add up to 7<BR>\n" );
document.write( "9 and -2<BR>\n" );
document.write( "6x^2-2x+9x-3=0<BR>\n" );
document.write( "2x*(3x-1)+3*(3x-1)=0<BR>\n" );
document.write( "(2x+3)*(3x-1)=0<BR>\n" );
document.write( "x=-3/2<BR>\n" );
document.write( "x=1/3<BR>\n" );
document.write( "and x=0<BR>\n" );
document.write( " </SPAN>\n" );
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