document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458023>Question 458023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I have a right triangle whose angles are 90 degrees, 53 degrees, and 37 degrees, and I know the hypotenuse is 6, what are the lengths of the other two sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314160 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If I have a right triangle whose angles are 90 degrees, 53 degrees, and 37 degrees, and I know the hypotenuse is 6, what are the lengths of the other two sides?<BR>\n" );
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document.write( "Draw the picture:<BR>\n" );
document.write( "Let the side opposite the 53 degree angle be \"a\"<BR>\n" );
document.write( "Let the side opposite the 37 degree angle be \"b\"<BR>\n" );
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document.write( "Sin(53) = a/6<BR>\n" );
document.write( "a = 6*sin(53) = 4.7918<BR>\n" );
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document.write( "cos(53) = b/6<BR>\n" );
document.write( "b = 6*cos(37) = 3.6109<BR>\n" );
document.write( "===========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );