document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458017>Question 458017</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help I have two problems: find the vertex,line of symmetry and graph the function:<BR>\n" );
document.write( "f(x)=-2x^2+2x+10\r<BR>\n" );
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document.write( "f(x)=2-x^2<BR>\n" );
document.write( "Thank you <BR>\n" );
document.write( "Gina </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314157 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)=-2x^2+2x+10<BR>\n" );
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document.write( "The vertex occurs where x = -b/(2a) = -2/(2*-2) = 1/2<BR>\n" );
document.write( "f(1/2) = -2(1/2)^2+2(1/2)+10 = -1/2 + 1 + 10 = 10 1/2 = 21/2<BR>\n" );
document.write( "Vertex:::(1/2,21/2)<BR>\n" );
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document.write( "f(x)=2-x^2<BR>\n" );
document.write( "x = -b/(2a) <BR>\n" );
document.write( "x = 0/(2*-2) = 0<BR>\n" );
document.write( "f(0) = 2<BR>\n" );
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document.write( "Vertex: (0,2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============= </SPAN>\n" );
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