document.write( "Question 458000: If x/3 -1 is twice as large as x/4 -3 , what is the value of x?\r
\n" );
document.write( "\n" );
document.write( "I've tried:\r
\n" );
document.write( "\n" );
document.write( "x/3 - 1 = 2(x/4 -3)\r
\n" );
document.write( "\n" );
document.write( "x/3 -1 = 2x/8 - 6\r
\n" );
document.write( "\n" );
document.write( "x/3 = 2x/8 - 5\r
\n" );
document.write( "\n" );
document.write( "8x/24 = 2x-5\r
\n" );
document.write( "\n" );
document.write( "8x = 48x-5\r
\n" );
document.write( "\n" );
document.write( "5 = 40x\r
\n" );
document.write( "\n" );
document.write( "x=8\r
\n" );
document.write( "\n" );
document.write( "but im not sure if its right. Please let me know the answer. Thanks! \n" );
document.write( "
Algebra.Com's Answer #314145 by robertb(5830)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "<==> \n" ); document.write( "\n" ); document.write( "==> \n" ); document.write( "\n" ); document.write( "==> \n" ); document.write( "\n" ); document.write( "==> x = 30, after cross-multiplication. \n" ); document.write( " |