document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=457992>Question 457992</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation x^2-9x+2k=0 has roots a and b.If a = 2b,find the value of k<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314144 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314144\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If b is one root, then 2b is the other.  Then from algebra, b*(2b) = 2k, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5E2+=+k ALIGN=MIDDLE  ALT=\"b%5E2+=+k\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Also the sum of the roots must be equal to the negative of -9/1 = -9, or b+2b = -(-9) = 9, or 3b = 9, or b = 3.  This is one root.  The other root is 2*3 = 6.  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=k+=+b%5E2+=+3%5E2+=+9 ALIGN=MIDDLE  ALT=\"k+=+b%5E2+=+3%5E2+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" >. </SPAN>\n" );
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