document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5927>Question 5927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I roll 5 regular dice out of a cup, what is<BR>\n" );
document.write( "1. The probability that I will get 5 of a kind.  I think the answer is 1 in 1296.\r<BR>\n" );
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document.write( "2. What is the probability that I will get two pair, i.e., 22335, 55422, even 33433 would count as two pair.  I come up with 1 in 34.56 rolls but I don't think this is correct.\r<BR>\n" );
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document.write( "Thanks,<BR>\n" );
document.write( "Bob Boose </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3141 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3141\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  There are 5 possible numbers of a kind,the prob. is 5/6^5 = 5/1296 (use math notation, not regular English)\r<BR>\n" );
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document.write( " Among 5 dices, 2 of them are the same number, then 2 of the remaining 3 are<BR>\n" );
document.write( " te same, the fifth one shouldbe different from the preevious two numbers.\r<BR>\n" );
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document.write( " There are 6*C(5,2)*5*C(3,2)*4 = 6*10*5*3*4 = 3600<BR>\n" );
document.write( " So the prob. of 2 pairs is 3600/6^5 = 100/6^3 = 25/54 (use fraction<BR>\n" );
document.write( " no decimals)\r<BR>\n" );
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document.write( " Kenny\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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