document.write( "Question 457889: A long distance trucker traveled 144 miles in one direction during a snow storm. The return trip in rainy weather was accomplished at double the speed and took 4 hours less time. Find the speed going. \n" ); document.write( "
Algebra.Com's Answer #314080 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
You need 2 equations: 1 for going
\n" ); document.write( "and 1 for the return trip
\n" ); document.write( "going:
\n" ); document.write( "\"+d+=+r%2At+\"
\n" ); document.write( "(1)\"+144+=+r%2At+\"
\n" ); document.write( "returning:
\n" ); document.write( "(2) \"+144+=+2r%2A%28t+-+4%29+\"
\n" ); document.write( "From (1):
\n" ); document.write( "\"+t+=+144%2Fr+\"
\n" ); document.write( "Substitute this into (2)
\n" ); document.write( "(2) \"+144+=+2r%2A%28144%2Fr+-+4%29+\"
\n" ); document.write( "(2) \"+144+=+288+-+8r+\"
\n" ); document.write( "(2) \"+8r+=+144+\"
\n" ); document.write( "(2) \"+r+=+18+\"
\n" ); document.write( "The speed going was 18 mi/hr
\n" ); document.write( "check answer:
\n" ); document.write( "(1)\"+144+=+18%2At+\"
\n" ); document.write( "(1)\"+t+=+8+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+144+=+2%2A18%2A%288+-+4%29+\"
\n" ); document.write( "(2) \"+144+=+36%2A4+\"
\n" ); document.write( "(2) \"+144+=+144+\"
\n" ); document.write( "OK\r
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