document.write( "Question 457864: Can you please provide me with a formula that I can use to solve this, and similar, problems? Thanks sooo much!\r
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\n" ); document.write( "\n" ); document.write( "The high school baseball team played 6 fewer games this year than last year but won 60% of the games played, compared with 50% of its games last year. The team won one more game this year than last year. How many games did the team play each year?
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Algebra.Com's Answer #314078 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"a\" = number of games played this year
\n" ); document.write( "given:
\n" ); document.write( "Last year team played this many games:
\n" ); document.write( "\"+a+%2B+6+\"
\n" ); document.write( "Games won this year:
\n" ); document.write( "\"+.6a+\"
\n" ); document.write( "Games won last year:
\n" ); document.write( "\"+.5%2A%28a+%2B+6%29+\"
\n" ); document.write( "and
\n" ); document.write( "\"+.6a+=+.5%2A%28a+%2B+6%29+%2B+1+\"
\n" ); document.write( "\"+.6a+=+.5a+%2B+3+%2B+1+\"
\n" ); document.write( "\"+.1a+=+4+\"
\n" ); document.write( "\"+a+=+40+\"
\n" ); document.write( "\"+a+%2B+6+=+46+\"
\n" ); document.write( "the team played 40 games this year and 46 last year
\n" ); document.write( "check answer:
\n" ); document.write( "This year they won 60% of games played
\n" ); document.write( "\"+.6%2A40+=+24+\"
\n" ); document.write( "They won 50% of games played last year:
\n" ); document.write( "\"+.5%2A%2840+%2B+6%29+=+23+\"
\n" ); document.write( "They won one more game this year than last year:
\n" ); document.write( "\"+24+-+23+=+1+\"
\n" ); document.write( "OK
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