document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=457764>Question 457764</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have no idea how to work this problem, I keep getting the wrong answer<BR>\n" );
document.write( "please help\r<BR>\n" );
document.write( "\n" );
document.write( "Solve: <BR>\n" );
document.write( "(y^2-5y)^2-8(y^2-5y)-84=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #314053 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=314053\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this is a quadratic in a quadratic\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "factoring ___ [(y^2 - 5y) - 14][(y^2 - 5y) + 6] = 0\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "y^2 - 5y - 14 = 0 ___ factoring ___ (y - 7)(y + 2) = 0 ___ y = 7 , y = -2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "y^2 - 5y + 6 = 0 ___ factoring ___ (y - 3)(y - 2) = 0 ___ y = 3 , y = 2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );