document.write( "Question 457722: the area of a rectangle is 12 y^3+6y^2+4y.one dimension is 2y.what is the other dimension? \n" ); document.write( "
Algebra.Com's Answer #314007 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "the area of a rectangle is \"A=ab\"\r
\n" ); document.write( "\n" ); document.write( "let \"A=12+y%5E3%2B6y%5E2%2B4y\" and one dimension \"a=+2y\"\r
\n" ); document.write( "\n" ); document.write( "find \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"A=ab\"\r
\n" ); document.write( "\n" ); document.write( "\"b=A%2Fa\"\r
\n" ); document.write( "\n" ); document.write( "\"b=%2812+y%5E3%2B6y%5E2%2B4y%29%2F2y\"\r
\n" ); document.write( "\n" ); document.write( "\"b=2y%286y%5E2%2B3y%2B2%29%2F2y\"\r
\n" ); document.write( "\n" ); document.write( "\"b=cross%282y%29%286y%5E2%2B3y%2B2%29%2Fcross%282y%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"b=6y%5E2%2B3y%2B2\"...solution\r
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