document.write( "Question 1055: Elise is four times as old as Amanda. In ten years, Amanda's age will be half of Elise's. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #314 by usyim88hk(158)\"\" \"About 
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\n" ); document.write( "Let x be the age of Amanda, so now we know
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\n" ); document.write( "x is Amanda's age (now)
\n" ); document.write( "4x is Elise's age (now)
\n" ); document.write( "x+10 is Amanda's age (after 10 years)
\n" ); document.write( "4x+10 or 2(x+10) is Elise's age (after 10 years)
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\n" ); document.write( "So now we know that 4x+10 is equal to (x+10)/2 because they are both the age of Elise after ten years, so now we can make an equation and solve it
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\n" ); document.write( "4x+10 = 2(x+10)
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\n" ); document.write( "Divide by 2 on both sides
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\n" ); document.write( "2x+5 = x+10
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\n" ); document.write( "subtract x from both sides
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\n" ); document.write( "x+5 = 10
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\n" ); document.write( "Subtract 5 from both sides
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\n" ); document.write( "x=5!!!
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\n" ); document.write( "So now we know that Amanda is five years old now, and Elise is 20 years old now \n" ); document.write( "
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