document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=457619>Question 457619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When three pumps A,B, and C are running together, they can pump 3200 gal an hour. When only A and B are running, 1900 gal per hour can be pumped. When only A and C are running, 1900 gal per hour can be pumped. What is the pumping capaciity of each pump? I set it up like this. \r<BR>\n" );
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document.write( "x+y+z=3200<BR>\n" );
document.write( "x+y=1900<BR>\n" );
document.write( "x+z=1900  \r<BR>\n" );
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document.write( "not sure where to continue im stuck </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313982 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You've gotten off to a good start,<BR>\n" );
document.write( "The three pumps are move water in gallons per hour.<BR>\n" );
document.write( "The three pumping rates will be shown as:  A, B & C.<BR>\n" );
document.write( "(You might as well use the given letters to help keep yourself consistent with the problem.)<BR>\n" );
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document.write( "Running together they pump 3200 gallons per hour.<BR>\n" );
document.write( "A + B + C = 3200<BR>\n" );
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document.write( "We also are told:<BR>\n" );
document.write( "A + B = 1900<BR>\n" );
document.write( "which means<BR>\n" );
document.write( "A = 1900 - B<BR>\n" );
document.write( "and<BR>\n" );
document.write( "B = 1900 - A<BR>\n" );
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document.write( "We also are told:<BR>\n" );
document.write( "A + C = 1900<BR>\n" );
document.write( "So,<BR>\n" );
document.write( "A = 1900 - C<BR>\n" );
document.write( "C = 1900 - A<BR>\n" );
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document.write( "Looking back at the first equation, we can substitute for B and C.<BR>\n" );
document.write( "A = A<BR>\n" );
document.write( "B = 1900-A<BR>\n" );
document.write( "C = 1900-A<BR>\n" );
document.write( "A +1900-A + 1900-A = 3200<BR>\n" );
document.write( "Collecting terms:<BR>\n" );
document.write( "A-2A + 3800 = 3200<BR>\n" );
document.write( "Simplify and subtract 3800 from both sides<BR>\n" );
document.write( "-A = -600<BR>\n" );
document.write( "Multiply both sides by -1 (or divide both sides by -1, it doesn't matter which):<BR>\n" );
document.write( "A = 600<BR>\n" );
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document.write( "That means<BR>\n" );
document.write( "B = 1900-600<BR>\n" );
document.write( "B = 1300<BR>\n" );
document.write( "and<BR>\n" );
document.write( "C = 1900-600<BR>\n" );
document.write( "C = 1300<BR>\n" );
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document.write( "A + B + C = 600 + 1300 + 1300<BR>\n" );
document.write( "A + B + C = 3200<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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