document.write( "Question 457590: Solve the equation 4sin^2 θ - 2 = 0 on the interval 0<θ<2pi. \n" ); document.write( "
Algebra.Com's Answer #313962 by stanbon(75887)\"\" \"About 
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Solve the equation 4sin^2 x - 2 = 0 on the interval 0< x <2pi.
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\n" ); document.write( "4sin^2(x) - 2 = 0
\n" ); document.write( "sin^2(x) = 1/2
\n" ); document.write( "sin(x) = +/-sqrt(2)/2
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\n" ); document.write( "In the interval 0 < x < 2pi, x = pi/4 or x = (3/4)pi
\n" ); document.write( "or x = (5/4)pi or (7/4)pi
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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