document.write( "Question 457547: 2log(x+1)-log(x+2)=log(2x-1)
\n" ); document.write( "base log 10
\n" ); document.write( "answer=1.3028
\n" ); document.write( "Can sir show me the step? \n" ); document.write( "

Algebra.Com's Answer #313931 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
2log(x+1)-log(x+2)=log(2x-1)
\n" ); document.write( "base log 10
\n" ); document.write( "answer=1.3028
\n" ); document.write( "..
\n" ); document.write( "2log(x+1)-log(x+2)=log(2x-1)
\n" ); document.write( "2log(x+1)-log(x+2)-log(2x-1)=0
\n" ); document.write( "log(x+1)^2-(log(x+2)+log(2x-1))=0
\n" ); document.write( "place under single log
\n" ); document.write( "log[(x+1)^2/(x+2)(2x-1)]=0
\n" ); document.write( "convert to exponential form (base(10) raised to log of number(0)=number (x+1)^2/(x+2)(2x-1))
\n" ); document.write( "10^0=(x+1)^2/(x+2)(2x-1)=1
\n" ); document.write( "(x+1)^2=(x+2)(2x-1)
\n" ); document.write( "x^2+2x+1=2x^2+3x-2
\n" ); document.write( "x^2+x-3=0
\n" ); document.write( "solve by quadratic formula as follows:
\n" ); document.write( "..
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "..
\n" ); document.write( "a=1, b=1, c=-3
\n" ); document.write( "x=[-1ąsqrt(1-4*1*-3)]/2*1
\n" ); document.write( "x=(-1ą√13)/2
\n" ); document.write( "x=(-1ą3.6056)/2
\n" ); document.write( "x=-2.3028 (reject, (x+1)>0)
\n" ); document.write( "or
\n" ); document.write( "x=1.3028 (ans) \n" ); document.write( "

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