document.write( "Question 457501: how do you re-write 3^x=90 as a logarithm and solve it? \n" ); document.write( "
Algebra.Com's Answer #313901 by Alan3354(69443)\"\" \"About 
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how do you re-write 3^x=90 as a logarithm and solve it?
\n" ); document.write( "As a log: \"log%283%2C90%29+=+x\"
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\n" ); document.write( "3^x=90
\n" ); document.write( "x*log(3) = log(90)
\n" ); document.write( "x = log(90)/log(3)
\n" ); document.write( "x =~ 4.0959
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