document.write( "Question 457495: how do you re-write 3^x=90 as a logarithm and solve it? \n" ); document.write( "
Algebra.Com's Answer #313900 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+3%5Ex+=+90+\"
\n" ); document.write( "\"+x%2Alog%283%29+=+log%2890%29+\"
\n" ); document.write( "\"+x+=+log%2890%29+%2F+log%283%29+\"
\n" ); document.write( "\"+x+=+1.9542+%2F+.4771+\"
\n" ); document.write( "\"+x+=+4.096+\"
\n" ); document.write( "check answer:
\n" ); document.write( "\"+3%5E4.096+=+90+\"
\n" ); document.write( "\"+90.009+=+90+\"
\n" ); document.write( "close enough
\n" ); document.write( "
\n" );