document.write( "Question 457485: I have to solve the equation x^2+ 12x-64=0 using the 6 step Indian process and I am not coming up with good numbers \n" ); document.write( "
Algebra.Com's Answer #313891 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The other tutor did the problem correctly but not by\r\n" );
document.write( "the 6-step Indian process. Here it is done by the \r\n" );
document.write( "6-step Indian process.\r\n" );
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document.write( "(1) Get the constant term off the left side of\r\n" );
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document.write( "    We add 64 to both sides:\r\n" );
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document.write( "    x² + 12x - 64 = 0\r\n" );
document.write( "         x² + 12x = 64 \r\n" );
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document.write( "(2) Multiply each term in the equation by four \r\n" );
document.write( "    times the coefficient of the x² term. \r\n" );
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document.write( "         x² + 12x = 64\r\n" );
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document.write( "    The coefficient of x² is 1\r\n" );
document.write( "    Four times 1 is 4\r\n" );
document.write( "    We multiply each term by 4\r\n" );
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document.write( "        4x² + 48x = 256      \r\n" );
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document.write( "(3) Square the coefficient of the original x term \r\n" );
document.write( "    and add it to both sides of the equation. \r\n" );
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document.write( "    The coefficient of the original x term was 12 \r\n" );
document.write( "    Square 12, get 144.\r\n" );
document.write( "    Add 144 to both sides:\r\n" );
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document.write( "          4x² + 48x = 256\r\n" );
document.write( "    4x² + 48x + 144 = 256 + 144\r\n" );
document.write( "    4x² + 48x + 144 = 400\r\n" );
document.write( "    The left side is a perfect square and may be\r\n" );
document.write( "    written as the square root of the the first\r\n" );
document.write( "    term plus the square root of the third term\r\n" );
document.write( "    in parentheses squared: \r\n" );
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document.write( "         (2x + 12)² = 400\r\n" );
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document.write( "(4) Take the square root of both sides. \r\n" );
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document.write( "            2x + 12 = ±20\r\n" );
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document.write( "(5) Set the left side of the equation equal to the \r\n" );
document.write( "    positive square root of the number on the right \r\n" );
document.write( "    side and solve for x. \r\n" );
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document.write( "            2x + 12 = 20\r\n" );
document.write( "                 2x = 8\r\n" );
document.write( "                  x = 4    \r\n" );
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document.write( "(6) Set the left side of the equation equal to the \r\n" );
document.write( "    positive square root of the number on the right \r\n" );
document.write( "    side and solve for x. \r\n" );
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document.write( "            2x + 12 = -20\r\n" );
document.write( "                 2x = -32\r\n" );
document.write( "                  x = -16\r\n" );
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document.write( "Edwin
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