document.write( "Question 457463: If there is have 38 square inches of cardboard to make a box that has a width of 1/2 inch and the height must be 5 inches how do you find the length the box should be
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Algebra.Com's Answer #313883 by ankor@dixie-net.com(22740)\"\" \"About 
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If there is 38 square inches of cardboard to make a box that has a width
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\n" ); document.write( "Surface area = 2(L*W) + 2(L*H) + 2(W*H)
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\n" ); document.write( "H = 5\"
\n" ); document.write( "W = .5\"
\n" ); document.write( "Find L
\n" ); document.write( "2(L*.5) + 2(L*5) + 2(.5*5) = 38
\n" ); document.write( "simplify, divide thru by 2, results
\n" ); document.write( "(L*.5) + (L*5) + (.5*5) = 19
\n" ); document.write( ".5L + 5L + 2.5 = 19
\n" ); document.write( "5.5L = 19 - 2.5
\n" ); document.write( "5.5L = 16.5
\n" ); document.write( "L = \"16.5%2F5.5\"
\n" ); document.write( "L = 3\" is the length
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\n" ); document.write( "Check this
\n" ); document.write( "2(3*.5) + 2(3*5) + 2(.5*5) =
\n" ); document.write( "3 + 30 + 5 = 38\r
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