document.write( "Question 47553This question is from textbook Beginning Algebra
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document.write( ": From TEXTBOOK\r
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document.write( "Need help solving this word problem and I need to show the equation that was used to get the solution.\r
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document.write( "A bus leaves a station at 1 pm., travelling westat an average rate of 44mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48mi/h. At what time will two buses be 274 mi apart?\r
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Algebra.Com's Answer #31388 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! You need two stopwatches and each must have a cellphone. The stop watches \n" ); document.write( "will show what time each started and the elapsed time untill they are \n" ); document.write( "274 miles apart. With ther cells, they can tell eachother how far they've \n" ); document.write( "gone from the start. \n" ); document.write( "t = 1st bus time \n" ); document.write( "t - 1 = 2nd bus time \n" ); document.write( "44t + 48(t - 1) = 274 \n" ); document.write( "44t + 48t -48 = 274 \n" ); document.write( "92t = 322 \n" ); document.write( "t = 3.5 hours \n" ); document.write( "This is the elapsed time for the 1st bus when they are 274 miles apart. \n" ); document.write( "1 PM + 3.5 hrs = 4:30 PM answer \n" ); document.write( "The time on the 2nd stopwatch will show 2.5 hours, and the 2nd bus left \n" ); document.write( "at 2 PM. So, it got to it's stopping point at \n" ); document.write( "2 PM + 2.5 hrs = 4:30 PM just as it should (they stop at the same time) \n" ); document.write( " |