document.write( "Question 457461: Solve by the addition method. (If the solution is inconsistent, enter INCONSISTENT. If the equations are dependent, give the answer in terms of x.)
\n" ); document.write( "9x + 3y = 6
\n" ); document.write( "6x + 2y = 5
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Algebra.Com's Answer #313875 by Edwin McCravy(20059)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "    9x + 3y = 6\r\n" );
document.write( "    6x + 2y = 5\r\n" );
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document.write( "To eliminate y.\r\n" );
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document.write( "1. Get the least common multiple of the coefficients of \r\n" );
document.write( "   y which are 3 and 2.  That's 6\r\n" );
document.write( "2. We need to make one the coefficient of y in one of \r\n" );
document.write( "   the equations to become 6 and the coefficient of y in \r\n" );
document.write( "   the other equation other become -6, so the terms in y \r\n" );
document.write( "   will cancel when we add the equations term by term.\r\n" );
document.write( "   We multiply the first equation through by 2, getting\r\n" );
document.write( "    18x + 6y =  12\r\n" );
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document.write( "   We multiply the second equation through by -3, getting\r\n" );
document.write( "   -18x - 6y = -15   \r\n" );
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document.write( "3. Now we have this system, and we add them term by term:\r\n" );
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document.write( "    18x + 6y =  12\r\n" );
document.write( "   -18x - 6y = -15\r\n" );
document.write( "   覧覧覧覧覧覧覧予r\n" );
document.write( "     0  +  0 =  -3\r\n" );
document.write( "           0 =  -3\r\n" );
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document.write( "4.  All the letters cancel out leaving only numbers.  When such\r\n" );
document.write( "    an equation is true the system is dependent and has infinitely\r\n" );
document.write( "    many solutions.  But when it is false, like this case 0 = -3, \r\n" );
document.write( "    the system is INCONSISTENT and there is no solution. \r\n" );
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document.write( "5.  The graphs of the two equations are parallel and therefore they\r\n" );
document.write( "    do not intersect to form a solution.  Here are their graphs.\r\n" );
document.write( "    The graph of the first equation is red and the graph of the second\r\n" );
document.write( "    equation is green: \r\n" );
document.write( "    \r\n" );
document.write( "    \r\n" );
document.write( "Edwin
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