document.write( "Question 34975: How many ways can you order a hamburger if you can order it with or without the following items: cheese, lettuce, tomatoes, pickles or onions? \n" ); document.write( "
Algebra.Com's Answer #313873 by JWG(21)![]() ![]() ![]() You can put this solution on YOUR website! My solution is much longer, but same answer. \r \n" ); document.write( "\n" ); document.write( "I read this problem as saying, \"How many ways can you make a hamburger with five different fixings?\" This means I can make a hamburger with all five fixings, or as little as none--just a plain burger with a bun. \r \n" ); document.write( "\n" ); document.write( "Five Fixings: 1 way \n" ); document.write( "Four Fixings: 5C4 = 5 ways \n" ); document.write( "Three Fixings: 5C3 = 10 ways \n" ); document.write( "Two Fixings: 5C2 = 10 ways \n" ); document.write( "One Fixing: 5 ways \n" ); document.write( "Zero Fixings: 1 way\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1+5+10+10+5+1 = 32\r \n" ); document.write( "\n" ); document.write( "32 ways to make a hamburger when there are five fixings to choose from, and amount of the five chosen vary. \n" ); document.write( " |