document.write( "Question 47556This question is from textbook Beginning Algebra
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document.write( "Science and Medicine category. I need help solving the word problem and showing the equation I used to get the solution:\r
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document.write( "Martina leaves home at 9:00 am., bicycling at a rate of 24mi/h. Two hours later, driving at the rate of 48mi/h, at what time will John catch up with Martina? \n" );
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Algebra.Com's Answer #31386 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! This is a problem of related rates. \n" ); document.write( "The most important information, and the easiest to miss, \n" ); document.write( "is at the very end. \n" ); document.write( "They meet. \n" ); document.write( "Each has traveled the same distance, since they started \n" ); document.write( "at the same place. \n" ); document.write( "Let \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( "so, just call the distance \n" ); document.write( " \n" ); document.write( "When they meet, John's time will be 2 hours less \n" ); document.write( " \n" ); document.write( "24 = Martina's rate \n" ); document.write( "48 = John's rate \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So, Martina's time is 4 hours and JOhn's time is \n" ); document.write( "or 2 hours. If Martina left at 9 AM, then 4 hours later, it will \n" ); document.write( "be 1 PM (answer) \n" ); document.write( " |