document.write( "Question 47556This question is from textbook Beginning Algebra
\n" ); document.write( ": From the Textbook:\r
\n" ); document.write( "\n" ); document.write( "Science and Medicine category. I need help solving the word problem and showing the equation I used to get the solution:\r
\n" ); document.write( "\n" ); document.write( "Martina leaves home at 9:00 am., bicycling at a rate of 24mi/h. Two hours later, driving at the rate of 48mi/h, at what time will John catch up with Martina?
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Algebra.Com's Answer #31386 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
This is a problem of related rates.
\n" ); document.write( "The most important information, and the easiest to miss,
\n" ); document.write( "is at the very end.
\n" ); document.write( "They meet.
\n" ); document.write( "Each has traveled the same distance, since they started
\n" ); document.write( "at the same place.
\n" ); document.write( "Let \"d%28m%29\" = Martina's distance
\n" ); document.write( "Let \"d%28j%29\" = John's distance
\n" ); document.write( "\"d%28m%29+=+d%28j%29\"
\n" ); document.write( "so, just call the distance \"d\"
\n" ); document.write( "\"t\" = Martina's time
\n" ); document.write( "When they meet, John's time will be 2 hours less
\n" ); document.write( "\"t+-+2\" = John's time
\n" ); document.write( "24 = Martina's rate
\n" ); document.write( "48 = John's rate
\n" ); document.write( "\"d+=+24t\"
\n" ); document.write( "\"d+=+48%2A%28t+-+2%29\"
\n" ); document.write( "\"24t+=+48%2A%28t+-+2%29\"
\n" ); document.write( "\"24t+=+48t+-+96\"
\n" ); document.write( "\"24t+=+96\"
\n" ); document.write( "\"t+=+4\"
\n" ); document.write( "So, Martina's time is 4 hours and JOhn's time is \"4+-+2\" hours
\n" ); document.write( "or 2 hours. If Martina left at 9 AM, then 4 hours later, it will
\n" ); document.write( "be 1 PM (answer)
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