document.write( "Question 457451: If 7 more than 3x a number is added to a diffrence of 5x a number and 10 the resust is 3o find the number. Hi I am trying to help my daugghter and I need help. #2 how much of a 50 % acid Solution should be combined with 10% acid solution to make 200 ounces of a 40% solution. #3 twice the diffece of a number and eight is equal to three times the sum of the number and 3. Find the number. If you can show the work so I will be able to learn as well as show my child. Thank you. marjorygregory@gmail.com \n" ); document.write( "
Algebra.Com's Answer #313857 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If 7 more than 3 x a number is added to a difference of 5 x a number and 10 the result is 3o. Find the number. \n" ); document.write( "--- \n" ); document.write( "Equation: \n" ); document.write( "3x + 7 + 5x + 10 = 30 \n" ); document.write( "8x + 17 = 30 \n" ); document.write( "8x = 13 \n" ); document.write( "x = 13/8 \n" ); document.write( "===================== \n" ); document.write( "#2 how much of a 50% acid Solution should be combined with 10% acid solution to make 200 ounces of a 40% solution. \n" ); document.write( "------- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.50x + 0.10(200-x) = 0.40*200 \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "50x + 10*200-10x = 40*200 \n" ); document.write( "4ox = 30*200 \n" ); document.write( "x = 30*5 \n" ); document.write( "x = 150 ounces (amt. of 50% solution needed) \n" ); document.write( "--- \n" ); document.write( "200-x = 50 ounces (amt of 10% solution needed \n" ); document.write( "=================================================\r \n" ); document.write( "\n" ); document.write( "#3 twice the difference of a number and eight is equal to three times the sum of the number and 3. Find the number. \n" ); document.write( "--- \n" ); document.write( "2(x-8) = 3(x+3) \n" ); document.write( "2x-16 = 3x+9 \n" ); document.write( "x = -25 \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================\r \n" ); document.write( "\n" ); document.write( "If you can show the work so I will be able to learn as well as show my child. \n" ); document.write( " |