document.write( "Question 47545: The equation h = - 16t^2 + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180ft. \n" ); document.write( "
Algebra.Com's Answer #31379 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The equation h = - 16t^2 + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180ft.\r
\n" ); document.write( "\n" ); document.write( "Let h=180 and solve for t, as follows:\r
\n" ); document.write( "\n" ); document.write( "180=-16t^2+112t
\n" ); document.write( "-16t^2+112t-180=0
\n" ); document.write( "-4(2t-5)(2t-9)=0\r
\n" ); document.write( "\n" ); document.write( "The arrow is at height 180 ft at time=5/2 sec. and at time=9/2 sec.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "
\n" );