document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=457286>Question 457286</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a rectangular house is 25 1/3 yards, and the length is 22 feet. What is the width?\r<BR>\n" );
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document.write( "what are the steps involved, im not just looking for the answer, I just want to learn this. Thanks Kevin. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313778 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 25 1/3 = 76'<BR>\n" );
document.write( "p=2(L+w)<BR>\n" );
document.write( "2(22+w)=76<BR>\n" );
document.write( "44+2w=76<BR>\n" );
document.write( "2w=32<BR>\n" );
document.write( "w=16'<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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