document.write( "Question 457246: simplify the expression
\n" ); document.write( "\"+sqrt%282%29%2B+sqrt%281%2F2%29+\"
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Algebra.Com's Answer #313749 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
The general rule of thumb is that you do not leave a radical in the denominator.
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\n" ); document.write( "In this problem, you can begin by changing the \"sqrt%281%2F2%29\" to its equivalent form:
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\n" ); document.write( "\"sqrt%281%29%2Fsqrt%282%29\"
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\n" ); document.write( "When you substitute this into the original expression, it becomes:
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\n" ); document.write( "\"sqrt%282%29%2Bsqrt%281%29%2Fsqrt%282%29\"
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\n" ); document.write( "To add these two terms together they must both have a common denominator. You can make this happen by multiplying the first term by \"sqrt%282%29%2Fsqrt%282%29\" as follows:
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\n" ); document.write( "\"sqrt%282%29%2Asqrt%282%29%2Fsqrt%282%29%2Bsqrt%281%29%2Fsqrt%282%29\"
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\n" ); document.write( "Multiplying out the numerator in the first term \"sqrt%282%29%2Asqrt%282%29\" results in just 2. When you substitute this the expression becomes:
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\n" ); document.write( "\"2%2Fsqrt%282%29%2Bsqrt%281%29%2Fsqrt%282%29\"
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\n" ); document.write( "Since both terms have a common denominator, you can now add the numerators and place that sum over the common denominator.
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\n" ); document.write( "\"%282%2Bsqrt%281%29%29%2Fsqrt%282%29\"
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\n" ); document.write( "But \"sqrt%281%29=1\" and this can be substituted into the expression to get:
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\n" ); document.write( "\"%282%2B1%29%2Fsqrt%282%29\"
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\n" ); document.write( "And performing the addition in the numerator results in:
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\n" ); document.write( "\"3%2Fsqrt%282%29\"
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\n" ); document.write( "As stated early in this problem, the usual practice is to not leave a radical in the denominator. You can get rid of the radical in the denominator by multiplying this fraction by \"sqrt%282%29%2Fsqrt%282%29\".
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\n" ); document.write( "\"%283%2Fsqrt%282%29%29%2A%28sqrt%282%29%2Fsqrt%282%29%29\"
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\n" ); document.write( "The numerator becomes \"3%2Asqrt%282%29\" and the denominator is \"sqrt%282%29%2Asqrt%282%29\" which multiplies out to 2. Substituting these two results into the expression gives:
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\n" ); document.write( "\"%283%2Asqrt%282%29%29%2F2\"
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\n" ); document.write( "And that is the answer.
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\n" ); document.write( "Hope this helps you to understand the problem.
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