document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47100>Question 47100</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the logarithmic equation. be sure to reject any value of x that produces the logarithm of a negative number or the logarithm of 0\r<BR>\n" );
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document.write( "log2(x+2)=1 + log2 (x-5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31373 by </B><A HREF=/tutors/aboutme.mpl?userid=venca><B>venca(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first we can rewrite 1 as log2(2), so we will have an equation:<BR>\n" );
document.write( "log2(x+2) = log2(2) + log2(x-5) <BR>\n" );
document.write( "log2(x+2) = log2(2x-10), so we will recieve an equation<BR>\n" );
document.write( "x+2 = 2x-10<BR>\n" );
document.write( "x = 12\r<BR>\n" );
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document.write( "conditions:  x+2 > 0 => x > -2   &  x-5 > 0 => x > 5, so x must be grater than 5<BR>\n" );
document.write( "12 > 5, so it is correct solution\r<BR>\n" );
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document.write( " </SPAN>\n" );
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