document.write( "Question 456904: What is the equation of the ellipse with foci (0, 4), (0, -4) and vertices (0, 8), (0, -8)? \n" ); document.write( "
Algebra.Com's Answer #313721 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! What is the equation of the ellipse with foci (0, 4), (0, -4) and vertices (0, 8), (0, -8) \n" ); document.write( ".. \n" ); document.write( "Standard form of ellipse with horizontal major axis: (x-h)^2/a^2+(y-k)^2/b^2=1, (a>b), with (h,k) being the (x,y) coordinates of the center. \n" ); document.write( "Standard form of ellipse with vertical major axis: (x-h)^2/b^2+(y-k)^2/a^2=1, (a>b), with (h,k) being the (x,y) coordinates of the center. \n" ); document.write( "The difference between the two forms is the interchange of a^2 and b^2 \n" ); document.write( ".. \n" ); document.write( "Because the given x-coordinates of foci and vertices are the same at x=0, ellipse has a vertical major axis. \n" ); document.write( "length of major axis=16=2a \n" ); document.write( "center at (0,0) (midpoints of vertices and foci) \n" ); document.write( "a=8 \n" ); document.write( "a^2=64 \n" ); document.write( "c=half the distance between foci=8/2=4 \n" ); document.write( "c^2=16 \n" ); document.write( "c^2=a^2-b^2 \n" ); document.write( "b^2=a^2-c^2=64-16=48 \n" ); document.write( "b√48=6.93.. \n" ); document.write( ".. \n" ); document.write( "Equation:(x-0)^2/48+(y-0)^2/64=1 \n" ); document.write( "=x^2/48+y^2/64=1 \n" ); document.write( "see graph below as a visual check on the answers. note the center and end points of the ellipse. \n" ); document.write( ".. \n" ); document.write( "y=(64-64(x^2)/48)^.5\r \n" ); document.write( "\n" ); document.write( " |