document.write( "Question 457222: A father is six times as old as his son. Two years ago he was eight times as old. Find the son's age. \n" ); document.write( "
Algebra.Com's Answer #313717 by algebrahouse.com(1659)\"\" \"About 
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x = son's age now
\n" ); document.write( "6x = father's age now {father is six times as old as his son}\r
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\n" ); document.write( "\n" ); document.write( "x - 2 = son two years ago
\n" ); document.write( "6x - 2 = father two years ago\r
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\n" ); document.write( "\n" ); document.write( "6x - 2 = 8(x - 2) {two years ago the father was eight times as old as his son}
\n" ); document.write( "6x - 2 = 8x - 16 {used distributive property}
\n" ); document.write( "-2 = 2x - 16 {subtracted 6x from both sides}
\n" ); document.write( "14 = 2x {added 16 to both sides}
\n" ); document.write( "x = 7 {divided both sides by 2}\r
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\n" ); document.write( "\n" ); document.write( "son is 7 years old now
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