document.write( "Question 457222: A father is six times as old as his son. Two years ago he was eight times as old. Find the son's age. \n" ); document.write( "
Algebra.Com's Answer #313717 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! x = son's age now \n" ); document.write( "6x = father's age now {father is six times as old as his son}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x - 2 = son two years ago \n" ); document.write( "6x - 2 = father two years ago\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6x - 2 = 8(x - 2) {two years ago the father was eight times as old as his son} \n" ); document.write( "6x - 2 = 8x - 16 {used distributive property} \n" ); document.write( "-2 = 2x - 16 {subtracted 6x from both sides} \n" ); document.write( "14 = 2x {added 16 to both sides} \n" ); document.write( "x = 7 {divided both sides by 2}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "son is 7 years old now \n" ); document.write( "www.algebrahouse.com \n" ); document.write( " |