document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47531>Question 47531</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help in figuring out how to solve this problem.  It is very confusing to me. I'd like to know how to work it out.\r<BR>\n" );
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document.write( "Find the area of a regular octagon with side length 5cm and apothem 6cm.\r<BR>\n" );
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document.write( "Find the volume of a square pyramid with height 12cm and slant height 15cm. \r<BR>\n" );
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document.write( "Please help!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31368 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31368\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the area of a regular octagon with side length 5cm and apothem 6cm.<BR>\n" );
document.write( "Connect the center to each of the vertices thus forming eight triangles.<BR>\n" );
document.write( "The area of one of these triangles = (1/2)5*6= 15 cm^2<BR>\n" );
document.write( "The area of the octagon = 8(15)=120 cm^2<BR>\n" );
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document.write( "Find the volume of a square pyramid with height 12cm and slant height 15cm.\r<BR>\n" );
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document.write( "Draw a right triangle with slant height as the hypotenuse and height as <BR>\n" );
document.write( "one of the sides.  The base will be sqrt(15^2-12^2)= 9 cm\r<BR>\n" );
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document.write( "Then the diagonal of the base of the pyramid will be 18 cm<BR>\n" );
document.write( "Find the side of the base of the pyramid as side^2 + side^2=18^2<BR>\n" );
document.write( "2side^2=324<BR>\n" );
document.write( "side= sqrt(162) and area of base= 162 cm^2<BR>\n" );
document.write( "Then Volume= (1/3)Base*height<BR>\n" );
document.write( "=(1/3)(162)12= 648 cm^3\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
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