document.write( "Question 47530: find the area of a box with dimensions sqrt 3 + sqrt 5 (length) and sqrt 3 + sqrt 5 (height) \n" ); document.write( "
Algebra.Com's Answer #31367 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
find the area of a box with dimensions sqrt 3 + sqrt 5 (length) and sqrt 3 + sqrt 5 (height)\r
\n" ); document.write( "\n" ); document.write( "Use FOIL as follows:
\n" ); document.write( "F: sqrt3 * sqrt3 = 3
\n" ); document.write( "O: sqrt3 * sqrt5 = sqrt15
\n" ); document.write( "I: sqrt5 * sqrt3 = sqrt15
\n" ); document.write( "L: sqrt5 * sqrt% = 5\r
\n" ); document.write( "\n" ); document.write( "Combine to get:
\n" ); document.write( "8 + 2sqrt(15)\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );