document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=457079>Question 457079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If anyone can show the steps taken to complete this problem it would begreatly appreciated. I have been out of school for quite awhile and am still drawing a blank. (x-3)(2x-7)=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313626 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313626\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x-3)(2x-7)=0<BR>\n" );
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document.write( "If the product is zero, one of the factors must be zero.<BR>\n" );
document.write( "You can't multiply 2 things and get zero otherwise.<BR>\n" );
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document.write( "Either x - 3 = 0 --> x = 3<BR>\n" );
document.write( "or<BR>\n" );
document.write( "2x - 7 = 0 --> x = 7/2<BR>\n" );
document.write( "2 answers:  x = 3, x = 7/2<BR>\n" );
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