document.write( "Question 457055: X:Y = 5:3, Y:Z = 4:9
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Algebra.Com's Answer #313622 by Edwin McCravy(20081)\"\" \"About 
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document.write( "X:Y = 5:3, Y:Z = 4:9\r\n" );
document.write( "Find ratio X:Y:Z?\r\n" );
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document.write( "The idea is to multiply the terms of the ratios so as\r\n" );
document.write( "to get the second term of the first ratio equal to the\r\n" );
document.write( "first term of the second ratio.\r\n" );
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document.write( "The second term of the first ratio is 3 and the first\r\n" );
document.write( "term of the second ratio is 4.\r\n" );
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document.write( "Now find the least common multiple of 3 and 4, which is 12.\r\n" );
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document.write( "So we multiply both terms of the first ratio by 4 and\r\n" );
document.write( "both terms of the second ratio by 3.\r\n" );
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document.write( "X:Y = 5:3 = 5×4:3×4 = 20:12, \r\n" );
document.write( "Y:Z = 4:9 = 4×3:9×3 = 12:27\r\n" );
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document.write( "Therefore the ratio X:Y:Z = 20:12:27\r\n" );
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document.write( "Edwin

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