document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=456479>Question 456479</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write a cost function for the problem. Assume that the relationship is linear. <BR>\n" );
document.write( "Fixed cost, $ 100;  5 items cost $ 1790 to produce <BR>\n" );
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document.write( "A) <BR>\n" );
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document.write( "C(x) =  676x  + 100 <BR>\n" );
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document.write( "B) <BR>\n" );
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document.write( "C(x) =  338x  + 100 <BR>\n" );
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document.write( "C) <BR>\n" );
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document.write( "C(x) =  338x  + 1790 <BR>\n" );
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document.write( "D) <BR>\n" );
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document.write( "C(x) =  676x  + 1790 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313619 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313619\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the fixed cost is $100, we know that if we make zero items (x = 0), then the cost is $100. Hence, only one of A or B is correct. If we replace x = 5 into both cost functions, we see that answer choice B satisfies C(5) = 1790. So choice B is correct. </SPAN>\n" );
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