document.write( "Question 47331: A candy store sells malted milk balls for $2.50 per pound, and chocolate-covered raisins for $3.75 per pound. How many pounds of each should be used to make a 10 pound mixture that sells for $3.00 per pound?\r
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Algebra.Com's Answer #31361 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A candy store sells malted milk balls for $2.50 per pound, and chocolate-covered raisins for $3.75 per pound. How many pounds of each should be used to make a 10 pound mixture that sells for $3.00 per pound?\r \n" ); document.write( "\n" ); document.write( "MM Ball DATA: \n" ); document.write( " amount=x lbs ; value=2.5x dollars \n" ); document.write( "CC Raisin DATA: \n" ); document.write( " amount=10-x lbs ; value= 3.75(10-x)= 37.5-3.75x dollars \n" ); document.write( "Mix DATA: \n" ); document.write( " amount=10 lbs ; value= 3(10)= 30 dollars\r \n" ); document.write( "\n" ); document.write( "EQUATION: \n" ); document.write( "value + value = value \n" ); document.write( "2.5x + 37.5-3.75x = 30 \n" ); document.write( "-3.75x=-10 \n" ); document.write( " x= 2.667 lbs (amount of MM Balls) \n" ); document.write( "10-x=7.333 lbs (amount of CC Raisins)\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |