document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=457054>Question 457054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the complement of an angle is 22° less than one-third of its supplement, find the measure of the angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313601 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the measure of the angle\r<BR>\n" );
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document.write( "90 - x = the complement of the angle<BR>\n" );
document.write( "180-x  = the supplement of the angle\r<BR>\n" );
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document.write( "90-x  = (180-x)/3 - 22\r<BR>\n" );
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document.write( "90-x = 60 - x/3 -22\r<BR>\n" );
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document.write( " 90-60+22 = -x/3 + x\r<BR>\n" );
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document.write( "52 = 2x/3\r<BR>\n" );
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document.write( "x = 78\r<BR>\n" );
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document.write( "The measure of the angle is 78 degrees </SPAN>\n" );
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