document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=456995>Question 456995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a student invests two sums of money, $500 and $800, at different interest rates, receiving a total of $55 in interest after one year. the $500 investment receives an interest rate 2% lower than the interest rate for the $800 investment. find the interest rate for each investment. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313575 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let $800 investment be at x%<BR>\n" );
document.write( "$500 will be @ (x-2)%\r<BR>\n" );
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document.write( "..<BR>\n" );
document.write( "800*x%+500(x-2)% = 55\r<BR>\n" );
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document.write( "multiply by 100\r<BR>\n" );
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document.write( "800x+500x-1000=5500<BR>\n" );
document.write( "1300x= 5500+1000<BR>\n" );
document.write( "1300x= 6500<BR>\n" );
document.write( "/1300<BR>\n" );
document.write( "x= 5 % for $800 investment<BR>\n" );
document.write( "3% for $500 investment </SPAN>\n" );
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