document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=456179>Question 456179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A special vehicle for traveling on glacial ice has tires that are 4.8 ft in diameter.  If the vehicle travels at 3.5 mi/h, what is the angular velocity (in r/min) of the tire? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313571 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313571\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A special vehicle for traveling on glacial ice has tires that are 4.8 ft in diameter. If the vehicle travels at 3.5 mi/h, what is the angular velocity (in r/min) of the tire?<BR>\n" );
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document.write( "Using quantitative analysis method:\r<BR>\n" );
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document.write( "(3.5 mi/hr)*(rev/4.8&#960; ft)*(2&#960; rad/rev*(5280 ft/mi)*(hr/60min)<BR>\n" );
document.write( "all units and &#960; cancel out except rad/min<BR>\n" );
document.write( "=(3.5*2*5280)/(4.8*60) rad/min<BR>\n" );
document.write( "=128.33 rad/min (ans)<BR>\n" );
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document.write( "factors (ratios) used:<BR>\n" );
document.write( "rev/circumference=rev/&#960;*diameter=rev/4.8&#960; ft<BR>\n" );
document.write( "2&#960; rad/rev<BR>\n" );
document.write( "5280 ft/mi<BR>\n" );
document.write( "hr/60 min </SPAN>\n" );
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