document.write( "Question 456932: Could you please help me to solve this problem?\r
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document.write( "Must show work\r
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document.write( "A sample of 20 elements produced a mean of 58 and a standard deviation of 12. Assuming the population has a normal distribution, find the 90% confidence interval for the population mean. \n" );
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Algebra.Com's Answer #313568 by edjones(8007) You can put this solution on YOUR website! n=20, m=58, s=12 \n" ); document.write( "(a, b)=m +- z[a/2] * s/sqrt(n) \n" ); document.write( "(a, b)=58+-1.645*(12/sqrt(20)) The z for .9 confidence level 2 tailed is +-1.645 \n" ); document.write( "=58+-4.41 \n" ); document.write( "=(62.41, 53.59) \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |