document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=456918>Question 456918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 78m.  The length is 6m more then twice the width.  Find the dimension. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313546 by </B><A HREF=/tutors/aboutme.mpl?userid=spacesurfer><B>spacesurfer(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=spacesurfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have l = 6 + 2w from the problem itself.\r<BR>\n" );
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document.write( "Also 2l + 2w = 78 by definition of perimeter.\r<BR>\n" );
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document.write( "Hence 2(6+2w) + 2w = 78 or 12 + 4w = 78, and w = 11.\r<BR>\n" );
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document.write( "So, if w = 11, then l = 6 + 2*11 = 28.\r<BR>\n" );
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document.write( "Double check: 2*11 + 2*28 = 78 </SPAN>\n" );
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