document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=456930>Question 456930</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triangle, the ratio of the measures of the sides is 2:3:4 and the perimeter is 144. Find the measures of the sides on the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313543 by </B><A HREF=/tutors/aboutme.mpl?userid=spacesurfer><B>spacesurfer(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=spacesurfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313543\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is easy. You should try it.\r<BR>\n" );
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document.write( "2x + 3x + 4x = 144.<BR>\n" );
document.write( "9x = 144.<BR>\n" );
document.write( "x = 16. \r<BR>\n" );
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document.write( "So, side 1 = 2x = 2*16 = 32.<BR>\n" );
document.write( "side 2 = 3x = 3*16 = 48<BR>\n" );
document.write( "side 3 = 4x = 4*16 = 64.\r<BR>\n" );
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document.write( "The sides are 32, 48, 64, and 32+48+64 = 144. </SPAN>\n" );
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