document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47434>Question 47434</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1592009425/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A certain beer is 5% alcohol and another type of beer is 2% alcohol.How much of each type should be mixed to get 100L of beer which is 3.2% of alcohol? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31352 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> EQUATION:<BR>\n" );
document.write( "0.05(x)+0.02(100-x)=100(0.032)<BR>\n" );
document.write( "0.05x-0.02x=3.2-2<BR>\n" );
document.write( "0.03x=1.2<BR>\n" );
document.write( "x=40<BR>\n" );
document.write( "100-40=60<BR>\n" );
document.write( "Hence, for 5% alcohol --> 40 L and for 2% alcohol --> 60L<BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );