document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=456844>Question 456844</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Lane invested $16,000, part at 6% and part at 8%. If the total interest at the end of the year was $1,080, how much did she invest at 6%? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #313472 by </B><A HREF=/tutors/aboutme.mpl?userid=benni1013><B>benni1013(206)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=benni1013><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=313472\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here is what we know:<BR>\n" );
document.write( "1) The total interest is $1,080. We also know part was invested at 6% and the other at percent. This results in the first of two equations. .06x+.08y=$1,080.\r<BR>\n" );
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document.write( "2) We also know that together he invested $16,000. This is the second equation.<BR>\n" );
document.write( "x+y=$16,000\r<BR>\n" );
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document.write( "This sets up the equations to solve in a system of equations computation problem. .06x+.08y=$1,080 and x+y=$16,000.\r<BR>\n" );
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document.write( "This should help quite a bit. </SPAN>\n" );
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